document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161738>Question 1161738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hexagonal steel bar has the following description:\r<BR>\n" );
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document.write( "15 in. length.\r<BR>\n" );
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document.write( "A circular hole in middle; 1.5 in. in diameter. (extends length of bar).\r<BR>\n" );
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document.write( "Side of hexagon; 2 in.\r<BR>\n" );
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document.write( "Steel weighs .283 lbs. / cu. in.\r<BR>\n" );
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document.write( "Determine volume and weight.  \r<BR>\n" );
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document.write( "Not sure how to solve.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785347 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The cross section is a hexagon with side length 2 with a circle of radius 3/4 inches cut out.<br><BR>\n" );
document.write( "Area of hexagon: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283s%5E2sqrt%283%29%29%2F2+=+6sqrt%283%29 ALIGN=MIDDLE  ALT=\"%283s%5E2sqrt%283%29%29%2F2+=+6sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Area of circle: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28pi%29r%5E2+=+%28pi%29%289%2F16%29 ALIGN=MIDDLE  ALT=\"%28pi%29r%5E2+=+%28pi%29%289%2F16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Cross-sectional area: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6sqrt%283%29-%289%2F16%29%28pi%29 ALIGN=MIDDLE  ALT=\"6sqrt%283%29-%289%2F16%29%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "volume: cross-sectional area, times length (15 inches)<br><BR>\n" );
document.write( "weight: volume, times pounds per cubic inch<br><BR>\n" );
document.write( "Use a calculator....<br><BR>\n" );
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