document.write( "Question 1161726: A component (circle-shaped with a diameter measuring 60 cm) is stamped out of sheet steel. A square(with side measuring 30 cm) in the center of that circle is discarded. These components are stamped out of a continuous steel coil with a width of 70 cm. The stamping process requires a gap of 25mm between each component. The steel coil is supplied in lengths of 25 meters costing $200.\r
\n" ); document.write( "\n" ); document.write( "a) What is the approximate percentage of steel wasted including the center square?
\n" ); document.write( "b) Assuming minimal wastage, how many components can be produced from each 25-meter coil?
\n" ); document.write( "c) What is the approximate cost of a component if the scrap is sold at 50% of the cost?\r
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Algebra.Com's Answer #785338 by KMST(5328)\"\" \"About 
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b) You can stamp up to \"highlight%2840%29\" circles,
\n" ); document.write( "Stamping the 60cm diameter circles centered on the mid-width of the sheet, 25mm (2.5cm) apart from each other would allow us to stamp along the 25m (2500cm) steel coil
\n" ); document.write( "\"2500cm%2F%2860cm%2B2.5cm%29=40\"circles.
\n" ); document.write( "In fact \"40\" circles with \"40-1=39\" gaps between them, adding \"2.5cm\" per gaps adds to a length of
\n" ); document.write( "\"40%2A%2860cm%29%2B39%2A%282.5cm%29=2497.5cm\"
\n" ); document.write( "and we could use the \"2500cm-2497.5cm=2.5cm\" leftover length
\n" ); document.write( "to leave some space between the circles at the ends and the beginning and end of the coil.
\n" ); document.write( "Offsetting the circles so they are shifted a bit to the left and the right, makes the string of circles a little shorter, but not short enough to fit an additional circle.
\n" ); document.write( "The most you could offset centers is \"70cm-60cm=10cm\" ,
\n" ); document.write( "and making the distance between the centers centers \"AB=62.5cm\" , would make the circles look like this
\n" ); document.write( " with \"BC=10cm\" and \"AC=sqrt%2862.5%5E2%2B10%5E2%29\"\"cm=61.7cm\" .
\n" ); document.write( "Each pattern with 2 circles (red rectangle) takes up
\n" ); document.write( "\"30cm%2B61.7cm%2B30cm=121.7cm\" , so \"40\" circles require \"40%2B121.7=2434cm\" out of the \"2500cm\" length of the coil.
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\n" ); document.write( "a) The area of each circle is \"pi%2Aradius%5E2=pi%2A%2830cm%29%5E2=900pi\"\"cm%5E2\"
\n" ); document.write( "The area of the square cut off is \"%2830cm%29%2A%2830cm%29=900cm%5E2\" .
\n" ); document.write( "The area of each component stamped is
\n" ); document.write( "\"%28900pi-900%29\"\"cm%5E2=900%28pi-1%29\"\"cm%5E2=approx.\"\"900%283.1416-1%29=900%2A2.1416cm%5E2=1927.44cm%5E2\"
\n" ); document.write( "The total area of the \"40\" stamped components is
\n" ); document.write( "\"40%2A1927.44cm%5E2=77097.6cm%5E2\"
\n" ); document.write( "The area of a sheet coil \"70cm\" wide and \"2500cm\" long is
\n" ); document.write( "\"%2870cm%29%2A%282500cm%29=175000cm%5E2\" .
\n" ); document.write( "Out of that surface area \"77097.6cm%5E2\" turns into \"40\" components, and the rest is \"steel wasted including the center square\".
\n" ); document.write( "The surface area of the steel wasted including the center square\" is
\n" ); document.write( "\"175000cm%5E2-77097.6cm%5E2=97902.4cm%5E2\"
\n" ); document.write( "As a percentage of the \"175000cm%5E2\" in the coil, that is
\n" ); document.write( "\"%2897902.4%2F175000cm%5E2%29%2A%22100%25%22=%22approx.%22\"\"highlight%28%2255.9%25%22%29=%22approx.%22\"\"highlight%28%2256%25%22%29\"
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\n" ); document.write( "c) The \"%2256%25%22=56%2F100=0.56\" of the coil wasted represents a cost of \"0.56%2A%22%24200%22=%22%24112%22\" .
\n" ); document.write( "Selling it at \"%2250%25%22=50%2F100=0.5\" of the cost reclaims \"0.5%2A%22%24112%22=%22%2456%22\" ,
\n" ); document.write( "making the cost of \"40\" components \"%22%24200%22-%22%2456%22-%22%24144%22\" , and the cost per component
\n" ); document.write( "\"%22%24144%22%2F40=highlight%28%22%243.60%22%29\"
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