document.write( "Question 1161726: A component (circle-shaped with a diameter measuring 60 cm) is stamped out of sheet steel. A square(with side measuring 30 cm) in the center of that circle is discarded. These components are stamped out of a continuous steel coil with a width of 70 cm. The stamping process requires a gap of 25mm between each component. The steel coil is supplied in lengths of 25 meters costing $200.\r
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document.write( "a) What is the approximate percentage of steel wasted including the center square?
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document.write( "b) Assuming minimal wastage, how many components can be produced from each 25-meter coil?
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document.write( "c) What is the approximate cost of a component if the scrap is sold at 50% of the cost?\r
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Algebra.Com's Answer #785336 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See diagram. There are exactly 40 pieces of the 25-meter coil of steel that measure 62.5 cm -- the diameter of the required circle plus the required 25 mm (2.5 cm) gap.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For one of the pieces, the scrap is the portion outside of the circle and inside of the green square. The total area of one piece is 62.5 x 70 square cm. The area of the circle is 30²π cm², and the area of the square is 30² cm². So the area of scrap is (62.5 x 70) - 30²π + 30² cm², which, divided by the total area of the piece gives the scrap percentage.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The scrap percentage calculated above times the $200 cost of the coil gives the cost of the scrap. Half of that cost subtracted from the $200 gives the total cost of material for the 40 components produced. So (200 - (Scrap Cost/2))/40 gives the per component material cost.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do your own arithmetic. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |