document.write( "Question 107769: Solve each of the following by graphing
\n" ); document.write( "2x+y=8
\n" ); document.write( "2x-y=0
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Algebra.Com's Answer #78531 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Solve each of the following by graphing
\n" ); document.write( "\"2x+%2B+y+=+8\"\r
\n" ); document.write( "\n" ); document.write( "here is the graph:\r
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"2%2Ax%2B1%2Ay=8\"Start with the given equation
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\n" ); document.write( " \"1%2Ay=8-2%2Ax\" Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%281%29%288-2%2Ax%29\" Multiply both sides by \"1\"
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\n" ); document.write( " \"y=%281%29%288%29-%281%29%282%29x%29\" Distribute \"1\"
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\n" ); document.write( " \"y=8-%282%29x\" Multiply
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\n" ); document.write( " \"y=-2%2Ax%2B8\" Rearrange the terms
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\n" ); document.write( " \"y=-2%2Ax%2B8\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=-2\" (the slope) and \"b=8\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=0
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\n" ); document.write( " \"y=-2%2A%280%29%2B8\"
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\n" ); document.write( " \"y=0%2B8\" Multiply
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\n" ); document.write( " \"y=8\" Add
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\n" ); document.write( " So here's one point (0,8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=1
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\n" ); document.write( " \"y=-2%2A%281%29%2B8\"
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\n" ); document.write( " \"y=-2%2B8\" Multiply
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\n" ); document.write( " \"y=6\" Add
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\n" ); document.write( " So here's another point (1,6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax%2B8\" through the points (0,8) and (1,6)
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\n" ); document.write( " So from the graph we can see that the slope is \"-2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 1 units to get to the next point), the y-intercept is (0,\"8\")and the x-intercept is (\"4\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=8\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"8\").
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\n" ); document.write( " So we have one point (0,\"8\")
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\n" ); document.write( " Now since the slope is \"-2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"8\"), we can go down 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=-2%2Ax%2B8\"
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\n" ); document.write( " So this is the graph of \"y=-2%2Ax%2B8\" through the points (0,8) and (1,6)
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\n" ); document.write( "\n" ); document.write( "\"2x+-+y+=+0\"\r
\n" ); document.write( "\n" ); document.write( "here is the graph:\r
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"2%2Ax-1%2Ay=0\"Start with the given equation
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\n" ); document.write( " \"-1%2Ay=0-2%2Ax\" Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%28-1%29%280-2%2Ax%29\" Multiply both sides by \"-1\"
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\n" ); document.write( " \"y=%28-1%29%280%29%2B%281%29%282%29x%29\" Distribute \"-1\"
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\n" ); document.write( " \"y=0%2B%282%29x\" Multiply
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\n" ); document.write( " \"y=2%2Ax%2B0\" Rearrange the terms
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\n" ); document.write( " \"y=2%2Ax%2B0\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=2\" (the slope) and \"b=0\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=-4
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\n" ); document.write( " \"y=2%2A%28-4%29%2B0\"
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\n" ); document.write( " \"y=-8%2B0\" Multiply
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\n" ); document.write( " \"y=-8\" Add
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\n" ); document.write( " So here's one point (-4,-8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-3
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\n" ); document.write( " \"y=2%2A%28-3%29%2B0\"
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\n" ); document.write( " \"y=-6%2B0\" Multiply
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\n" ); document.write( " \"y=-6\" Add
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\n" ); document.write( " So here's another point (-3,-6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B0\" through the points (-4,-8) and (-3,-6)
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\n" ); document.write( " So from the graph we can see that the slope is \"2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,\"0\")and the x-intercept is (\"0\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=0\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"0\").
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\n" ); document.write( " So we have one point (0,\"0\")
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\n" ); document.write( " Now since the slope is \"2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"0\"), we can go up 2 units
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\n" ); document.write( "
\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=2%2Ax%2B0\"
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B0\" through the points (0,0) and (1,2)
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