document.write( "Question 1161706: Mattie Evans drove 200 miles in the same amount of time that it took a turbo propeller plane to travel 920 miles. The speed of the plane was 180
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document.write( "mph faster than the speed of the car. Find the speed of the plane. \n" );
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Algebra.Com's Answer #785309 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is the distance-rate-time table for both the car and plane \n" ); document.write( "
\n" ); document.write( "You start off filling out the distances for each. Those are the given numeric values. The time t is the same for both the car and plane. The rate or speed is found using the formula r = d/t, which comes from d = r*t. The table is optional, but may be handy to keep track of everything.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We know that the plane goes 180 mph faster than the car, so this means \n" ); document.write( "plane's speed = (car's speed) + 180 \n" ); document.write( "920/t = (200/t) + 180 \n" ); document.write( "920 = 200 + 180t \n" ); document.write( "on the last step, I multiplied every term by t to clear out the fractions\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here, let's solve for t \n" ); document.write( "920 = 200 + 180t \n" ); document.write( "920-200 = 180t \n" ); document.write( "720 = 180t \n" ); document.write( "180t = 720 \n" ); document.write( "t = 720/180 \n" ); document.write( "t = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Both car and plane travel for t = 4 hours. \n" ); document.write( "Doing so, the car's speed is r = d/t = 200/4 = 50 mph \n" ); document.write( "and the plane's speed is r = d/t = 920/4 = 230 mph \n" ); document.write( "The plane's speed is 230-50 = 180 mph greater than that of the car\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: plane's speed = 230 mph \n" ); document.write( " \n" ); document.write( " |