document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161670>Question 1161670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The electrical resistance R of a wire varies directly as the length L and inversely as the square of the diameter d. Obtain an equation connecting R,L and d if R =27 when L=3 and d=2. Calculate (a) value of R when L=8, d=3<BR>\n" );
document.write( "(b) value of d when R=16,L=18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #785271 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=785271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The electrical resistance R of a wire varies directly as the length L and inversely as the square of the diameter d. <BR>\n" );
document.write( "Obtain an equation connecting R,L and d if R =27 when L=3 and d=2.<BR>\n" );
document.write( "----<BR>\n" );
document.write( "R = k*L/d^2 ---- k = a constant<BR>\n" );
document.write( "27 = k*3/4<BR>\n" );
document.write( "k = 36<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( "Calculate (a) value of R when L=8, d=3<BR>\n" );
document.write( "Sub, do arithmetic<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "(b) value of d when R=16,L=18<BR>\n" );
document.write( "Sub, do arithmetic<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );