document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107764>Question 107764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular saw has a diameter of 18cm and 22 teeth. What is the spacing between teeth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78526 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 22 teeth and 22 spaces between them.<BR>\n" );
document.write( "The Circumference - the amount of space taken by the teeth (22s where s is the amount of space taken by one tooth) is equal to the total amount of space occupied by nothing ... Divide that by the 22 spaces between the teeth and you get the individual space between two teeth.<BR>\n" );
document.write( "(C - 22s)/22<BR>\n" );
document.write( "(18(pi) - 22s)/22<BR>\n" );
document.write( "9(pi)/11 - s    ... where s is in cm </SPAN>\n" );
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