document.write( "Question 1161600: On a certain run of a
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document.write( "commuter train, the average number of passengers is 476
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document.write( "and the standard deviation is 22. Assume the variable is
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document.write( "normally distributed. If the train makes the run, find the
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document.write( "probability that the number of passengers will be\r
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document.write( "a. Between 476 and 500 passengers
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document.write( "b. Less than 450 passengers
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document.write( "c. More than 510 passengers \n" );
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Algebra.Com's Answer #785228 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! a. Between 476 and 500 passengers \n" ); document.write( " \n" ); document.write( "z1 = \n" ); document.write( " \n" ); document.write( "Look up 0 on a z-table. The result is 0.5000. \n" ); document.write( " \n" ); document.write( "z2 = \n" ); document.write( " \n" ); document.write( "Look up 1.09 on a z-table. The result is 0.8621. \n" ); document.write( " \n" ); document.write( "Subtract 0.5000 from 0.8621 to get a result of 0.3621. \n" ); document.write( " \n" ); document.write( "---------------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "b. Less than 450 passengers \n" ); document.write( " \n" ); document.write( "z = \n" ); document.write( " \n" ); document.write( "Look up -1.18 on a z-table. The result is 0.1190. \n" ); document.write( " \n" ); document.write( "---------------------------------------------------------------- \n" ); document.write( " \n" ); document.write( "b. More than 510 passengers \n" ); document.write( " \n" ); document.write( "z = \n" ); document.write( " \n" ); document.write( "Look up 1.55 on a z-table. The result is 0.9394. This is the probability that FEWER than 510 passengers are on the train. So, the probability that MORE than 510 passengers are on the train is 1 - 0.9394...or, 0.0606. |