document.write( "Question 1161568: One ton of lead is used to make pipe, 2 in. outside diameter, 1/4 in. thick.\r
\n" ); document.write( "\n" ); document.write( "Determine pipe length. \r
\n" ); document.write( "\n" ); document.write( "5% is allowed for waste.\r
\n" ); document.write( "\n" ); document.write( "Lead weighs 710 lbs. per cu. ft.\r
\n" ); document.write( "\n" ); document.write( "One ton = 2000 lbs.\r
\n" ); document.write( "\n" ); document.write( "1900 lbs. available.\r
\n" ); document.write( "\n" ); document.write( "Pipe is a hollow cylinder.\r
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Algebra.Com's Answer #785177 by ikleyn(52873) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            The tutor @Boreal made almost uncountable number of errors on the way, starting from his first line.\r
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\n" ); document.write( "\n" ); document.write( "            He was so hurry that even did not check his calculations, that have nothing common with reality.\r
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document.write( "Outer radius of the pipe is R_out = 1 inch.\r\n" );
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document.write( "Interior radius of the pipe is 1/4 inch less: R_in = 3/4 in.\r\n" );
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document.write( "The transverse section area of the pipe is   =  =  square inches.\r\n" );
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document.write( "The volume of the one foot of the pipe is   in^3 =  in^3 = 16.485 in^3.\r\n" );
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document.write( "The weight of 1 foot of the pipe is   = 6.773 lbs.\r\n" );
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document.write( "The length of the pipe =  = 280.52 ft.\r\n" );
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document.write( "Take  5%  off for waste :   the final length is  0.95*280.52 = 266.5 ft.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "For many years working with engineers and scientists, I learned that there are 1000 ways to make mistakes
\n" ); document.write( "and to get wrong answers at the end in the result, and there is only ONE WAY to do the job correctly.\r
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