document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107746>Question 107746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of a rectangular parking lot is 10 meters less than twice its width, and the perimeter is 400 meters, find the length of the parking lot. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78515 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter(p) of a rectangle=2*Length(l) + 2*Width(w)or p=2l+2w<BR>\n" );
document.write( "Let w=width\r<BR>\n" );
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document.write( "Then length(l)=2*w-10\r<BR>\n" );
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document.write( "p=2(2w-10)+2w=400  get rid of parens (distributive law)\r<BR>\n" );
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document.write( "400=4w-20+2w  add 20 to both sides<BR>\n" );
document.write( "400+20=4w-20+20+2w  collect like terms\r<BR>\n" );
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document.write( "420=6w  divide both sides by 6\r<BR>\n" );
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document.write( "w=70 meters------------------------width<BR>\n" );
document.write( "2w-10=2*70-10=140-10=130 meters -------length\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "400=2*70+2*130<BR>\n" );
document.write( "400=140+260<BR>\n" );
document.write( "400=400\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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