document.write( "Question 1161533: Hi\r
\n" ); document.write( "\n" ); document.write( "Given that a^3-b^3 = (a-b)(a^2+ab +b^2) and that (a+b)^2 = 121 and ab = 24\r
\n" ); document.write( "\n" ); document.write( "Where a>b find the value of a^3-b^3.\r
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Algebra.Com's Answer #785129 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If then .\r
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\n" ); document.write( "\n" ); document.write( "\ b\ \Right\ a\ =\ 8\ \text{and}\ b\ =\ 3\">\r
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\n" ); document.write( "\n" ); document.write( "\ b\ \Right\ a\ =\ -3\ \text{and}\ b\ =\ -8\">\r
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\n" ); document.write( "\n" ); document.write( "Case 1:\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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