document.write( "Question 107725: if every fourth trick- or- treater is a vampire, and every 6th a robot , how many of each will you see if 75 trick- or- treaters come to your door?\r
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document.write( "i need the steps on how u solve this problem.\r
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document.write( "THANK YOU:) \n" );
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Algebra.Com's Answer #78512 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! I just drew up the whole thing. 75 events can be shown as 15 groups \n" ); document.write( "of 5 each (75 = 15*5). I wanted to see if the robots and vampires \n" ); document.write( "would try to come at the same time \n" ); document.write( "------------------------------------------- \n" ); document.write( "1 2 3 4 5 6 7 8 9 0 I 2 3 4 5 \n" ); document.write( "V 1 1 R V 1 1 1 V R 1 1 V 1 1 \n" ); document.write( "2 2 2 V R 2 2 V 2 2 R V 2 2 2 \n" ); document.write( "3 3 V 3 3 R V 3 3 3 V R 3 3 V \n" ); document.write( "R V 4 4 4 V R 4 4 V 4 4 R V 4 \n" ); document.write( "V R 5 5 V 5 5 R V 5 5 5 V R 5 \n" ); document.write( "------------------------------------------- \n" ); document.write( "There are 15 groups of 5 each. Every 4th is a Vampire. Every 6th is \n" ); document.write( "a Robot. If you look at the patterns of R's and V's they arediagonals \n" ); document.write( "going in opposite directions, so a V & R can never end up in the same \n" ); document.write( "position. Counting V's I get 19. Counting R's I get 12 \n" ); document.write( " |