document.write( "Question 1161499: A study found that 73% of elementary students buy lunch at school at least once a month. How large a sample would be necessary to estimate the true proportion within 3 percentage points with 95% confidence? \n" ); document.write( "
Algebra.Com's Answer #785062 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! then half-interval or margin of error is 0.03=z*sqrt(p*(1-p)/n) \n" ); document.write( "0.03=1.96*sqrt(0.73*0.27)/n) \n" ); document.write( "square both sides \n" ); document.write( "0.0009=3.8416*0.73*0.27/n \n" ); document.write( "n=841.31 or 842\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |