document.write( "Question 107733: Simplify the expressions by using the properties of rational exponents. Write the final answer using positive exponents only.\r
\n" ); document.write( "\n" ); document.write( "(50p^-1q)^1/2 (this is the numerator)
\n" ); document.write( "(2pq^-3)^1/2 (this is the denominator)\r
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\n" ); document.write( "\n" ); document.write( "I don't have a clue. Please help.
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Algebra.Com's Answer #78503 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"%28%2850p%5E%28-1%29q%29%5E%281%2F2%29%29%2F%282pq%5E%28-3%29%29%5E%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "Yes, indeed that is ugly. But fortunately, the exponent on the numerator and denominator is the same, so we can take this first step:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%2850p%5E%28-1%29q%29%2F%282pq%5E%28-3%29%29%29%5E%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, any coefficient with a negative exponent can move from the numerator to the denominator, or vice versa, making the exponent positive. That's because of the rule \"a%5E%28-n%29=1%2F%28a%5En%29\":\r
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\n" ); document.write( "\n" ); document.write( "\"%28%2850q%5E4%29%2F%282p%5E2%29%29%5E%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "And then divide the 50 by the 2 in the denominator to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%2825q%5E4%29%2F%28p%5E2%29%29%5E%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, recall that \"a%5E%281%2F2%29=sqrt%28a%29\". Applying this rule we get:\r
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