document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107675>Question 107675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary and the measure of one of them is 20% less than three times the measure of the other. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78502 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=180 OR X=180-Y<BR>\n" );
document.write( "X=.2(3Y)<BR>\n" );
document.write( "180-Y=.6Y<BR>\n" );
document.write( "1.6Y=180<BR>\n" );
document.write( "Y=180/1.6<BR>\n" );
document.write( "Y=112.5 FOR THE LARGER ANGLE.<BR>\n" );
document.write( "X=.2(3*112.5)<BR>\n" );
document.write( "X=.2(337.5)<BR>\n" );
document.write( "X=67.5 FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "112.5=67.5=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );