document.write( "Question 1161446: Business. A small company has an assembly line that
\n" ); document.write( "produces three types of widgets. The basic widget is sold for
\n" ); document.write( "$10 per unit, the midprice widget for $12 per unit, and the
\n" ); document.write( "top-of-the-line widget for $15 per unit. The assembly line
\n" ); document.write( "has a daily capacity of producing 325 widgets that may be
\n" ); document.write( "sold for a total of $3825. Find the quantity of each type of
\n" ); document.write( "widget produced on a day when twice as many basic widgets
\n" ); document.write( "as top-of-the-line widgets are produced.
\n" ); document.write( "

Algebra.Com's Answer #785006 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Let x be the number of the top-of-the-line widgets.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then the number of the basic widgets is 2x, according to the condition,\r\n" );
document.write( "\r\n" );
document.write( "and the rest  (325-x-2x) = (325-3x)  widgets are mid-price.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then the total revenue equation is\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    10*(2x) + 12*(325-3x) + 15x = 3825   dollars.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "From the equation,\r\n" );
document.write( "\r\n" );
document.write( "    x = \"%283825-12%2A325%29%2F%2820-+36+%2B+15%29\" = 75.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  75 top-of-the-line widgets;  2*75 = 150 basic widgets; and the rest (325 - 75 - 150) = 100  are mid-price widgets.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved // using one single equation in one unknown (!)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );