document.write( "Question 1161439: 322base5รท4base5
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document.write( "Figure the problem using base 5blocks.
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document.write( "Figure the problem using standard algorithm.
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document.write( "Figure the problem using repeated subtraction. \n" );
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Algebra.Com's Answer #784997 by greenestamps(13327) You can put this solution on YOUR website! \n" ); document.write( "(1) I don't know what \"base 5 blocks\" are.... \n" ); document.write( "(2) To divide using long division, it is helpful to have a multiplication table for 4 in base 5: \n" ); document.write( "1*4 = 4 (base 10) = 4 (base 5) \n" ); document.write( "2*4 = 8 = 13 (base 5) \n" ); document.write( "3*4 = 12 = 22 (base 5) \n" ); document.write( "4*4 = 16 = 31 (base 5) \n" ); document.write( "Then in the subtraction part of the algorithm, you of course need to do the subtraction in base 5. \r\n" ); document.write( "\r\n" ); document.write( " 4 1 remainder 3\r\n" ); document.write( " --------\r\n" ); document.write( " 4 ) 3 2 2\r\n" ); document.write( " 3 1 [4*4 = 31]\r\n" ); document.write( " ------\r\n" ); document.write( " 1 2 [subtract; bring down the next digit]\r\n" ); document.write( " 4 [4*1 = 4]\r\n" ); document.write( " ---\r\n" ); document.write( " 3 [subtract to get the remainder] \n" ); document.write( "(3) Solving using repeated subtraction is straightforward, but gives us a lot of practice in base 5 arithmetic.... \r\n" ); document.write( "1 322-4 = 313\r\n" ); document.write( "2 313-4 = 304\r\n" ); document.write( "3 304-4 = 300\r\n" ); document.write( "4 300-4 = 241\r\n" ); document.write( "5 241-4 = 232\r\n" ); document.write( "6 232-4 = 223\r\n" ); document.write( "7 223-4 = 214\r\n" ); document.write( "8 214-4 = 210\r\n" ); document.write( "9 210-4 = 201\r\n" ); document.write( "10 201-4 = 142\r\n" ); document.write( "11 142-4 = 133\r\n" ); document.write( "12 133-4 = 124\r\n" ); document.write( "13 124-4 = 120\r\n" ); document.write( "14 120-4 = 111\r\n" ); document.write( "15 111-4 = 102\r\n" ); document.write( "16 102-4 = 43\r\n" ); document.write( "17 43-4 = 34\r\n" ); document.write( "18 34-4 = 30\r\n" ); document.write( "19 30-4 = 21\r\n" ); document.write( "20 21-4 = 12\r\n" ); document.write( "21 12-4 = 3 \n" ); document.write( "We subtracted 4 21 times, which is 41 in base 5; and we were left with a remainder of 3. So again we got the result 322 divided by 4 in base 5 = 41 remainder 3. \n" ); document.write( " \n" ); document.write( " |