document.write( "Question 1161028: 5. a) A 70-Kg box is slid along the floor by a 400-N force. The coefficient of friction between the box and the floor is 0.50 when the box is sliding. Calculate acceleration of the box?\r
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document.write( "5. b) Suppose this box (70-Kg) is pulled by a 400-N force at an angle of 30 to the horizontal .\r
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document.write( "Find the X and the Y components.\r
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document.write( "5. c) Determine the acceleration of the box \n" );
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Algebra.Com's Answer #784989 by KMST(5328)![]() ![]() You can put this solution on YOUR website! NOTE: If you have to \"show your work\" you may want to use the number of decimal places/significant figures that would make your teacher/instructor/professor happy. \n" ); document.write( "I tend to use more decimal places than needed during intermediate calculations and round at the end, because that is what is required in my line of work. \n" ); document.write( " \n" ); document.write( "a) Assuming a horizontal, level floor, the normal force (perpendicular to the surface, pressing the box into the floor) is \n" ); document.write( " \n" ); document.write( "The horizontal friction force opposing the movement is \n" ); document.write( " \n" ); document.write( "The net force on the box is \n" ); document.write( " \n" ); document.write( "The box will accelerate in the direction of the 400N force. \n" ); document.write( "The acceleration will be \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "b) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "c) Now the normal force is \n" ); document.write( " \n" ); document.write( "That will make the friction force opposing the movement \n" ); document.write( " \n" ); document.write( "The net horizontal force acting on the box will be \n" ); document.write( " \n" ); document.write( "Acting on a mass of 70kg, that net horizontal force will produce a horizontal acceleration of \n" ); document.write( " |