document.write( "Question 1161028: 5. a) A 70-Kg box is slid along the floor by a 400-N force. The coefficient of friction between the box and the floor is 0.50 when the box is sliding. Calculate acceleration of the box?\r
\n" ); document.write( "\n" ); document.write( "5. b) Suppose this box (70-Kg) is pulled by a 400-N force at an angle of 30 to the horizontal .\r
\n" ); document.write( "\n" ); document.write( "Find the X and the Y components.\r
\n" ); document.write( "\n" ); document.write( "5. c) Determine the acceleration of the box
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Algebra.Com's Answer #784989 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
NOTE: If you have to \"show your work\" you may want to use the number of decimal places/significant figures that would make your teacher/instructor/professor happy.
\n" ); document.write( "I tend to use more decimal places than needed during intermediate calculations and round at the end, because that is what is required in my line of work.
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\n" ); document.write( "a) Assuming a horizontal, level floor, the normal force (perpendicular to the surface, pressing the box into the floor) is
\n" ); document.write( "\"%2870kg%29%2A%289.807ms%5E9-2%29=686.49N\"
\n" ); document.write( "The horizontal friction force opposing the movement is
\n" ); document.write( "\"0.50%2A%28686.49N%29=343.245N\"
\n" ); document.write( "The net force on the box is
\n" ); document.write( "\"400N-343.245N=56.755N\"
\n" ); document.write( "The box will accelerate in the direction of the 400N force.
\n" ); document.write( "The acceleration will be
\n" ); document.write( "\"56.755N%2F%2270+kg%22=highlight%280.81ms%5E%28-2%29%29\"
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\n" ); document.write( "b)
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\n" ); document.write( "\"F%5Bx%5D=%28400N%29%2Acos%2830%5Eo%29=%28400N%29%2A0.8660=highlight%28346.4N%29\"
\n" ); document.write( "\"F%5By%5D=%28400N%29%2Asin%2830%5Eo%29=%28400N%29%2A0.5000=highlight%28200N%29\"\r
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\n" ); document.write( "c) Now the normal force is
\n" ); document.write( "\"686.49N-F%5By%5D=686.49N-200N=486.49N\"
\n" ); document.write( "That will make the friction force opposing the movement
\n" ); document.write( "\"%28486.49N%29%2A0.50=243.245N\"
\n" ); document.write( "The net horizontal force acting on the box will be
\n" ); document.write( "\"346.4N-243.245N=103.155N\"
\n" ); document.write( "Acting on a mass of 70kg, that net horizontal force will produce a horizontal acceleration of
\n" ); document.write( "\"103.155N%2F%2270+kg%22=highlight%281.47ms%5E%28-2%29%29\"
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