document.write( "Question 1161303: A sample of 150 U.S. adults is composed of 100 women and 50 men. Estimate the confidence interval for the male population with 99% confidence.
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document.write( "CI=YZ(y)\r
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document.write( "99% CI= 0.23 to 0.43
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document.write( " How do I show my work? \n" );
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Algebra.Com's Answer #784982 by Boreal(15235) You can put this solution on YOUR website! z*SE, where z is the particular z associated with the CI and SE is sqrt(p(1-p)/n)\r \n" ); document.write( "\n" ); document.write( "the half-interval is z(0.995)*sqrt{(1/3)(2/3)/150} or sqrt (p*(1-p)/n) \n" ); document.write( "=2.576*sqrt(2/1350)=0.0992 \n" ); document.write( "the interval is 1/3+/-0.0992 or (0.234, 0.432) \n" ); document.write( " |