document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161389>Question 1161389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is able to save N50.00 of his salary in a certain year and afterwards saves in any one year N20.00 more than he saved in the preceding year. how long does it take him to save N4370.00? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784978 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sum=an=4370. This equals (n/2)(2a1+(n-1)d). a1=50 and d=20<BR>\n" );
document.write( "so multiplying by 2, and 8740=n(100+20n-20)<BR>\n" );
document.write( "100n+20n^2-20n=8740<BR>\n" );
document.write( "20n^2+80n-8740=0<BR>\n" );
document.write( "n^2+4n-437=0<BR>\n" );
document.write( "n=-4+/-sqrt(1764)/2<BR>\n" );
document.write( "=(1/2)(-4+42), positive root only<BR>\n" );
document.write( "=19 years ANSWER<BR>\n" );
document.write( "divide everything by 10<BR>\n" );
document.write( "5/7/9/11/13/15/17/19/21/23/25/27/29/31/33/35/37/39/41=437<BR>\n" );
document.write( " </SPAN>\n" );
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