document.write( "Question 1161423: Solve exactly, where possible, giving answers in radians. Approximate answers must be rounded to 2 decimal places: \r
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Algebra.Com's Answer #784958 by Edwin McCravy(20067)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"sec%5E2%28a%29%2B5+=+3tan%5E2%28a%29\"\r\n" );
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document.write( "Use 1 + tan²θ = sec²θ\r\n" );
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document.write( "\"1%2Btan%5E2%28a%29%2B5+=+3tan%5E2%28a%29\"\r\n" );
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document.write( "\"6=2tan%5E2%28theta%29\"\r\n" );
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document.write( "\"3=tan%5E2%28theta%29\"\r\n" );
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document.write( "\"%22%22+%2B-+sqrt%283%29=tan%5E%22%22%28theta%29\"\r\n" );
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document.write( "The ± tells us that θ can be 60° or π/3 in all 4 quadrants.\r\n" );
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document.write( "[Note that adding π∙n takes care of π/3 in all 4 quadrants,\r\n" );
document.write( "and we don't have to add 2π∙n.]\r\n" );
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document.write( "Edwin
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