document.write( "Question 1161365: Given the following table:
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document.write( "y | 15 30 60 90
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document.write( "p(y)| .2 .3 .4 .1\r
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document.write( "Find: Mean, Standard deviation, and probability that the time is within 1 SD of its mean.\r
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document.write( "Any help would be appreciated, thanks! \n" );
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Algebra.Com's Answer #784891 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "Mean = 45 \n" ); document.write( "Standard deviation = 23.2379000772446 (approximate; round however you need to) \n" ); document.write( "Probability the time is within one standard deviation of the mean = 0.7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===================================================================================== \n" ); document.write( "Work Shown:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (a): Finding the mean\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find the mean, we multiply each y value by its corresponding probability p(y) value as shown in the table below \n" ); document.write( "
\n" ); document.write( "Example: in row 1 we have y*p(y) = 15*0.2 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add up the values in the y*p(y) column to get the mean \n" ); document.write( "mean = 3+9+24+9 = 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We will use the mean later when it comes to calculating the standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (b): Finding the standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First we must construct a new column labeled y^2*p(y). This is a column of values where we square the y values, and then multiply those squares by their corresponding p(y) values. For instance, row 1 has y = 15, so y^2 = 15^2 = 225, which leads to y^2*p(y) = 225*0.2 = 45. It's a coicidence that this also happens to be the value of the mean. The other rows are computed in a similar fashion.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's the updated table \n" ); document.write( "
\n" ); document.write( "We then add up everything in that new y^2*p(y) column which yields \n" ); document.write( "45+270+1440+810 = 2565\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, we square the mean. \n" ); document.write( "mu = mean \n" ); document.write( "mu = 45 found earlier \n" ); document.write( "mu^2 = 45^2 \n" ); document.write( "mu^2 = 2025\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract this result off the sum of the y^2*p(y) column to get the variance sigma^2 \n" ); document.write( "sigma^2 = (sum of y*p(y) column) - ( mu^2 ) \n" ); document.write( "sigma^2 = 2565 - 2025 \n" ); document.write( "sigma^2 = 540\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lastly, we apply the square root to both sides to get the value of sigma, which is the standard deviation \n" ); document.write( "sigma^2 = 540 \n" ); document.write( "sigma = sqrt(540) \n" ); document.write( "sigma = 23.2379000772446 which is approximate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We will use this for part (c), along with the mean as well. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Part (c): probability that the time is within 1 SD of its mean\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From part (b), we found the approximate standard deviation to be 23.2379000772446\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add and subtract this from the mean to get the values of U and L respectively \n" ); document.write( "L = lower value that is 1 std dev from the mean \n" ); document.write( "L = mu-sigma \n" ); document.write( "L = 45 - 23.2379000772446 \n" ); document.write( "L = 21.7620999227553 which is approximate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = upper value that is 1 std dev from the mean \n" ); document.write( "U = mu+sigma \n" ); document.write( "U = 45 + 23.2379000772446 \n" ); document.write( "U = 68.2379000772447\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The values of L and U were approximately 21.7620999227553 and 68.2379000772447\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Looking at the table, we are searching for y values that are between those L and U values. \n" ); document.write( "This applies for y = 30 and y = 60 only \n" ); document.write( "In other words, y = 30 and y = 60 make the inequality 21.7620999227553 < y < 68.2379000772447 true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So from here, we add up the corresponding probabilities for those y values \n" ); document.write( "0.3 + 0.4 = 0.7\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |