document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161358>Question 1161358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves a town at 50 kilometers per hour. How long will it take a second car, travelling at 95 kilometers per hour, to catch the first car if it leaves 1 hour later? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784870 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second car starts 50 km behind<BR>\n" );
document.write( "it is moving at 45 km/h faster than the other, so it will take 50/45 or 10/9 hours to catch the first car\r<BR>\n" );
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document.write( "or <BR>\n" );
document.write( "the second catches the first in x hours<BR>\n" );
document.write( "distance for the first car is 50(1+x) and for the second car 95x. Since they are together, the distance is the same.<BR>\n" );
document.write( "50+50x=95x<BR>\n" );
document.write( "45x=50<BR>\n" );
document.write( "x-50/45=10/9. </SPAN>\n" );
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