document.write( "Question 1161302: Find three consecutive even integers such that the sum of 6 times the first, 5 times the second, and 4 times the third is 356.\r
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Algebra.Com's Answer #784818 by saw(34)\"\" \"About 
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Solution.
\n" ); document.write( "Let x = 1st number
\n" ); document.write( "Let x+2 = 2nd number
\n" ); document.write( "Let x+4 = 3rd number
\n" ); document.write( "Condition given
\n" ); document.write( "6x+5(x+2)+4(x+4) = 356
\n" ); document.write( "Distribute 5 through the parenthesis
\n" ); document.write( "6x+5x+10+4(x+4) = 356
\n" ); document.write( "Distribute 4 through the parenthesis
\n" ); document.write( "6x+5x+10+4x+16 = 356
\n" ); document.write( "Collect the like terms
\n" ); document.write( "15x+10+16 = 356
\n" ); document.write( "Add the numbers
\n" ); document.write( "15x+26 = 356
\n" ); document.write( "Move constant to the right side of the equation and change its sign
\n" ); document.write( "15x = 356-26
\n" ); document.write( "Subtract the numbers
\n" ); document.write( "15x = 330
\n" ); document.write( "Divide both sides of the equation by 15
\n" ); document.write( "x = 22
\n" ); document.write( "Use substitution
\n" ); document.write( "x+2 = 22+2 = 24
\n" ); document.write( "Use substitution
\n" ); document.write( "x+4 = 22+4 = 26
\n" ); document.write( "Three consecutive even integers are 22, 24, and 26.\r
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