document.write( "Question 1161302: Find three consecutive even integers such that the sum of 6 times the first, 5 times the second, and 4 times the third is 356.\r
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Algebra.Com's Answer #784811 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Very often, a formal algebraic solution to a problem like this is made simpler by choosing the variable x as the middle number. In this problem, that leads to

\n" ); document.write( "\"6%28x-2%29%2B5%28x%29%2B4%28x%2B2%29+=+356\"
\n" ); document.write( "\"6x-12%2B5x%2B4x%2B8+=+356\"
\n" ); document.write( "\"15x-4+=+356\"
\n" ); document.write( "\"15x+=+360\"
\n" ); document.write( "\"x+=+24\"

\n" ); document.write( "The three numbers are 22, 24, and 26.

\n" ); document.write( "If a formal algebraic solution is not required, you can get to the solution quickly using a bit of estimation.

\n" ); document.write( "Since the numbers are three consecutive even integers, the sum of 6 times the first, 5 times the second, and 4 times the third is very close to 15 times the second.

\n" ); document.write( "Estimating 15 times an even number is about 356 leads immediately to 24 as the middle number, again making the three numbers 22, 24, and 26.

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