document.write( "Question 107727: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #78481 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle? \n" ); document.write( "------------- \n" ); document.write( "Let the width be \"w\" \n" ); document.write( "Then the length is \"4w+1\" \n" ); document.write( "------------------------- \n" ); document.write( "Area = width*length \n" ); document.write( "65 = w(4w+1) \n" ); document.write( "65 = 4w^2+w \n" ); document.write( "---------- \n" ); document.write( "Rearrange: \n" ); document.write( "4w^2+w-65 = 0 \n" ); document.write( "w = [-1 +- sqrt(1 - 4*4*-65)]/8 \n" ); document.write( "w = [-1 +- sqrt(1041)]/ \n" ); document.write( "w = [-1 +- 32.2645...]/8 \n" ); document.write( "w = 3.908...cm (width of the rectangle) \n" ); document.write( "4w+1 = 16.6322...cm (length of the rectangle) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |