document.write( "Question 107727: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #78481 by stanbon(75887)\"\" \"About 
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The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 65 cm2, find the dimensions of the rectangle?
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\n" ); document.write( "Let the width be \"w\"
\n" ); document.write( "Then the length is \"4w+1\"
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\n" ); document.write( "Area = width*length
\n" ); document.write( "65 = w(4w+1)
\n" ); document.write( "65 = 4w^2+w
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\n" ); document.write( "Rearrange:
\n" ); document.write( "4w^2+w-65 = 0
\n" ); document.write( "w = [-1 +- sqrt(1 - 4*4*-65)]/8
\n" ); document.write( "w = [-1 +- sqrt(1041)]/
\n" ); document.write( "w = [-1 +- 32.2645...]/8
\n" ); document.write( "w = 3.908...cm (width of the rectangle)
\n" ); document.write( "4w+1 = 16.6322...cm (length of the rectangle)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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