document.write( "Question 1161243: I draw a card from a standard 52-card deck. If I draw an Ace, I win 1 dollar. If I draw a 2 through 10, I win a number of dollars equal to the value of the card. If I draw a face card (Jack, Queen, or King), I win 20 dollars. If I draw a $\clubsuit$, my winnings are doubled, and if I draw a $\spadesuit$, my winnings are tripled. (For example, if I draw the $8\clubsuit$, then I win 16 dollars.) What would be a fair price to pay to play the game? Express your answer as a dollar value rounded to the nearest cent.\r
\n" ); document.write( "\n" ); document.write( "Your answer should be a number with two digits after the decimal point, like $21.43$.
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\n" ); document.write( "This is expected value. So for the ace, it would be E = (1) 4/52 as a decimal(.923076923) and for the face cards it would be (12/52 ) as a decimal ??(20) so it would be E= (1)(923076923) + (20)(0.230769231) the rest i don't know, please help
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Algebra.Com's Answer #784748 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If you draw a red Ace, you get $1. There are 2 red aces in the deck, so the probability of drawing a red Ace is 1/26. The expected value of drawing a red ace is then (1/26)(1) which is approximately $0.04.\r
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\n" ); document.write( "\n" ); document.write( "The club Ace gets you $2, 1 club ace, 1/52 times $2 is the same $0.04.\r
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\n" ); document.write( "\n" ); document.write( "The spade Ace is worth $3, 1/52 times $3 gives E(AS) = $0.06.\r
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\n" ); document.write( "\n" ); document.write( "For the 2s, you have 2 times 1/26, 4 times 1/52, and 6 times 1/52.\r
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\n" ); document.write( "\n" ); document.write( "The rest are summarized in the following table:\r
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document.write( " A♥♦	 1	  1/26	 $0.04 \r\n" );
document.write( " A ♣	 2	  1/52	 $0.04 \r\n" );
document.write( " A ♠	 3	  1/52	 $0.06 \r\n" );
document.write( " 2♥♦	 2	  1/26	 $0.08 \r\n" );
document.write( " 2 ♣	 4	  1/52	 $0.08 \r\n" );
document.write( " 2 ♠	 6	  1/52	 $0.12 \r\n" );
document.write( " 3♥♦	 3	  1/26	 $0.12 \r\n" );
document.write( " 3 ♣	 6	  1/52	 $0.12 \r\n" );
document.write( " 3 ♠	 9	  1/52	 $0.17 \r\n" );
document.write( " 4♥♦	 4	  1/26	 $0.15 \r\n" );
document.write( " 4 ♣	 8	  1/52	 $0.15 \r\n" );
document.write( " 4 ♠	12	  1/52	 $0.23 \r\n" );
document.write( " 5♥♦	 5	  1/26	 $0.19 \r\n" );
document.write( " 5 ♣	10	  1/52	 $0.19 \r\n" );
document.write( " 5 ♠	15	  1/52	 $0.29 \r\n" );
document.write( " 6♥♦	 6	  1/26	 $0.23 \r\n" );
document.write( " 6 ♣	12	  1/52	 $0.23 \r\n" );
document.write( " 6 ♠	18	  1/52	 $0.35 \r\n" );
document.write( " 7♥♦	 7	  1/26	 $0.27 \r\n" );
document.write( " 7 ♣	14	  1/52	 $0.27 \r\n" );
document.write( " 7 ♠	21	  1/52	 $0.40 \r\n" );
document.write( " 8♥♦	 8	  1/26	 $0.31 \r\n" );
document.write( " 8 ♣	16	  1/52	 $0.31 \r\n" );
document.write( " 8 ♠	24	  1/52	 $0.46 \r\n" );
document.write( " 9♥♦	 9	  1/26	 $0.35 \r\n" );
document.write( " 9 ♣	18	  1/52	 $0.35 \r\n" );
document.write( " 9 ♠	27	  1/52	 $0.52 \r\n" );
document.write( "10♥♦	10	  1/26	 $0.38 \r\n" );
document.write( "10 ♣	20	  1/52	 $0.38 \r\n" );
document.write( "10 ♠	30	  1/52	 $0.58 \r\n" );
document.write( " F♥♦	20	  3/26	 $2.31 \r\n" );
document.write( " F ♣	40	  3/52	 $2.31 \r\n" );
document.write( " F ♠	60	  3/52	 $3.46 \r\n" );
document.write( "			$15.48\r\n" );
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\n" ); document.write( "\n" ); document.write( "The expected value of the game is the sum of the individual expected values. By the way, don't add the numbers in the expected value column -- they are all rounded and you will get an incorrect sum. The correct sum of the unrounded values which is then rounded to two digits is shown.
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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