document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161207>Question 1161207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maryia has saved $63.5in dimes and loonies.if she has 5 dimes fewer than two thirds the number of loonies.how many coins of each type does marysua have!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784701 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x number of loonies<BR>\n" );
document.write( "(2/3)x-5 number of dimes, worth (2/3)*(1/10)*x-.50<BR>\n" );
document.write( "money is x+(1/15)x-.5=$63.5<BR>\n" );
document.write( "(16/15)x=64<BR>\n" );
document.write( "x=64*15/16=60 loonies ($60)<BR>\n" );
document.write( "and 2/3 of them minus 5 is 35 dimes ($3.50) </SPAN>\n" );
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