document.write( "Question 107704: One number is 3 less than another. If 10 times the smaller number minus 3 times the larger number is 33, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #78466 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Let the first number be x. Then the other number must be x + 3.\r \n" ); document.write( "\n" ); document.write( "10 times the first number is 10x, and 3 times the other number is 3(x + 3) so subtracting gives you:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The smaller number is 6, and the larger is 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |