document.write( "Question 107704: One number is 3 less than another. If 10 times the smaller number minus 3 times the larger number is 33, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #78466 by solver91311(24713)\"\" \"About 
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Let the first number be x. Then the other number must be x + 3.\r
\n" ); document.write( "\n" ); document.write( "10 times the first number is 10x, and 3 times the other number is 3(x + 3) so subtracting gives you:\r
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\n" ); document.write( "\n" ); document.write( "\"10x-3%28x%2B3%29=+33\"
\n" ); document.write( "\"10x-3x-9=33\"
\n" ); document.write( "\"7x-9=33\"
\n" ); document.write( "\"7x=42\"
\n" ); document.write( "\"x=6\"\r
\n" ); document.write( "\n" ); document.write( "The smaller number is 6, and the larger is 9.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"10%2A6-3%2A9=33\"
\n" ); document.write( "\"60-27=33\" Check\r
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