document.write( "Question 1160975: John surfs the website on a regular basis. Suppose the time he spent surfing the website per day is normally distributed, µ = 8 minutes and σ = 2 minutes. If you select a random sample of 4 sessions,
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document.write( "a. What is the probability that the sample mean is less than 8 minutes?
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document.write( "b. What is the probability that sample mean is between 8 and 10 minutes?
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document.write( "c. If you select a random sample of 16 sessions, what is the probability that a as sample mean is between 8 and 9 minutes?
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document.write( "d. Explain the differences in the results of (b) and (c).
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Algebra.Com's Answer #784622 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! a. 50%, since E(X bar)=8 minutes\r \n" ); document.write( "\n" ); document.write( "z=(x bar-mean)/sigma/sqrt(n) \n" ); document.write( "sigma/sqrt(n)=2/2=1 \n" ); document.write( "so b is looking at 8 and 10 minutes with sd 1 \n" ); document.write( "this is z between 0 and 2, which is 0.4772.\r \n" ); document.write( "\n" ); document.write( "for 16 now the sd will be 2/sqrt(16)=0.5 \n" ); document.write( "and the same probability of 0.4772 will occur. \r \n" ); document.write( "\n" ); document.write( "It is much more likely that the sampling distribution will be narrower and distances from the expected value of 8 (in this instance) won't be as much as the sample size increases. \n" ); document.write( " |