document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1161162>Question 1161162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman with a basket of eggs finds that if she removes the eggs from a basket 3 or 7 at a time there is always one egg left. However if she removes the eggs 5 at a time there are no eggs left. If the basket holds up to 100 eggs how many eggs does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784612 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second digit is either a 0 or a 5<BR>\n" );
document.write( "Therefore, need a multiplier of 3 and 7 that ends in 9 or 4. There are no suitable ones for 9 that are evenly divisible by both 3 and 7<BR>\n" );
document.write( "for 4, there is the product (3*7)*4 or 84<BR>\n" );
document.write( "Then there would be 85 eggs, which satisfies the second part. ANSWER<BR>\n" );
document.write( "Removing them 3 at a time, 84 could be removed<BR>\n" );
document.write( "same for 7 at a time.  No other product of 3 and 7 ends in four for both when < 100 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );