document.write( "Question 1161110: Graph f(x)= {1-x,if x<0 2x-1, if x> with a line under it 0
\n" ); document.write( "Find f(3) and f(0) and f(-2)
\n" ); document.write( "It’s all one question
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Algebra.Com's Answer #784594 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "The notation f(3) means f(x) when x = 3. We replace x with 3. Since x = 3, we need to look where this fits.\r
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\n" ); document.write( "\n" ); document.write( "We have \"if x < 0\", but x = 3 is not smaller than zero. So we move onto the next piece which has \"x+%3E=+0\". This second piece says \"when \"x%3E=0\", we have f(x) = 2x-1\"\r
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\n" ); document.write( "\n" ); document.write( "So we plug x = 3 into this to get
\n" ); document.write( "f(x) = 2x-1
\n" ); document.write( "f(3) = 2(3)-1
\n" ); document.write( "f(3) = 6-1
\n" ); document.write( "f(3) = 5\r
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\n" ); document.write( "\n" ); document.write( "Similarly, x = 0 makes \"x+%3E=+0\" true, so we use the second piece still\r
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\n" ); document.write( "\n" ); document.write( "f(x) = 2x-1
\n" ); document.write( "f(0) = 2(0)-1
\n" ); document.write( "f(0) = 0-1
\n" ); document.write( "f(0) = -1\r
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\n" ); document.write( "\n" ); document.write( "Finally, we want to find the value of f(x) when x = -2. This time we don't use the second piece. This is because x = -2 makes \"x+%3C+0\" true.\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "f(x) = 1-x
\n" ); document.write( "f(-2) = 1-(-2)
\n" ); document.write( "f(-2) = 1+2
\n" ); document.write( "f(-2) = 3
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