document.write( "Question 1161067: A woman is 5 years older than her husband and 10 times as old as their daughter. In 14 years, the sum of their ages will be 100. How old are the woman, husband, and daughter now? \n" ); document.write( "
Algebra.Com's Answer #784486 by ankor@dixie-net.com(22740)\"\" \"About 
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A woman is 5 years older than her husband
\n" ); document.write( " w = h + 5
\n" ); document.write( "or
\n" ); document.write( " h = w - 5
\n" ); document.write( "and 10 times as old as their daughter.
\n" ); document.write( " w = 10d
\n" ); document.write( "or divide by 10
\n" ); document.write( " d = .1w
\n" ); document.write( " In 14 years, the sum of their ages will be 100.
\n" ); document.write( "(w+14) + (h+14) + (d+14) = 100
\n" ); document.write( "w + h + d + 42 = 100
\n" ); document.write( "w + h + d = 100 - 42
\n" ); document.write( "w + h + d = 58
\n" ); document.write( "replace h with (w-5), replace d with .1w
\n" ); document.write( "w + (w-5) + .1w = 58
\n" ); document.write( "2.1w = 58 + 5
\n" ); document.write( "2.1w = 63
\n" ); document.write( "w = 63/2.1
\n" ); document.write( "w = 30 yrs is the woman's age
\n" ); document.write( "then
\n" ); document.write( "h = 30 - 5
\n" ); document.write( "h = 25 yr is the husband's age
\n" ); document.write( "and
\n" ); document.write( "d = .1(30)
\n" ); document.write( "d = 3 yrs is the daughter's \r
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