document.write( "Question 1161025: 3. A bus moving in straight line at a speed of 20 m/s begins to slow down at a constant rate of 3 𝑚/𝑠2 each second. Find how far it goes before stopping? \n" ); document.write( "
Algebra.Com's Answer #784440 by ikleyn(52781)\"\" \"About 
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document.write( "Again, I will consider the problem as if it comes from Physics.\r\n" );
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document.write( "Then the breaking force is the product of the mass \"m\"  and acceleration \"a\"\r\n" );
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document.write( "         \"F%5Bbreaking%5D\" = ma.\r\n" );
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document.write( "while the kinetic energy is  \"%28mv%5E2%29%2F2\".\r\n" );
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document.write( "Now apply the Energy conservation law: The kinetic energy is equal to the work of the force.\r\n" );
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document.write( "The force is  \"F%5Bbreaking%5D\",  and its work is the product of the force by the breaking distance \"x\", which is the unknown in this problem.\r\n" );
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document.write( "So you have this equation\r\n" );
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document.write( "    \"%28mv%5E2%29%2F2\" = m*a*x.\r\n" );
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document.write( "Cancel the mass in both side and obtain\r\n" );
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document.write( "    x = \"%28%28v%5E2%2F2%29%29%2Fa\" = \"v%5E2%2F%282a%29\" = \"20%5E2%2F%282%2A3%29\" = 66.666... = 66.7 meters (rounded).\r\n" );
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document.write( "ANSWER.  The breaking distance is  66.7 meters.\r\n" );
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