document.write( "Question 107682: Ricky drove from Town A to Town B in 3 hours. His return trip from Town B to Town A took 5 hours because he drove 15 miles per hour slower on the return trip.
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document.write( "How fast did Ricky drive on the trip from Town A to Town B? \n" );
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Algebra.Com's Answer #78441 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! You must begin with the firmly held conviction that nobody picked up Town A and moved it during the 8+ hours that Ricky was gone.\r \n" ); document.write( "\n" ); document.write( "We know that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the initial trip, we only know that t = 3, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the return trip, we know that t = 5 and r is 15 mph slower, so:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the distance going is the same as the distance returning, we can say:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify and solve:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check:\r \n" ); document.write( "\n" ); document.write( "Does |