document.write( "Question 1160885: A rectangular billboard sign has a length that is four yards longer than twice its width, x If the area of the sign is 30 square yards, which equation could be used to find the dimensions in yards of the sign? \n" ); document.write( "
| Algebra.Com's Answer #784291 by ikleyn(52879)     You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " W*(2W+4) = 30 square yards (the area).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " W*(W+2) = 15.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, 15 is presented as the product of two factors that differ by 2.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, guessing mentally, W = 3; W + 2 = 5.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Or you can solve the equation (1) formally.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. W = 3 yards; L = 2W + 4 = 2*3+4 = 10 yards.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |