document.write( "Question 1160883: The perimeter of a rectangle is 150 cm. The length is 15 cm greater than the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #784287 by ankor@dixie-net.com(22740)\"\" \"About 
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perimeter of a rectangle is 150 cm.
\n" ); document.write( "2L + 2w = 150
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + w = 75
\n" ); document.write( " The length is 15 cm greater than the width.
\n" ); document.write( "L = w + 15
\n" ); document.write( "In L + w = 75, replace L with (w+15)
\n" ); document.write( "w + 15 + w = 75
\n" ); document.write( "2w = 75 - 15
\n" ); document.write( "2w = 60
\n" ); document.write( " /2
\n" ); document.write( " w = 30
\n" ); document.write( "then
\n" ); document.write( "L = 30 + 15
\n" ); document.write( "L = 45
\n" ); document.write( " Find the dimensions. 45 by 15
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check using perimeter
\n" ); document.write( "2(45) + 2(30) = 150 \n" ); document.write( "
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