document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160876>Question 1160876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a circle with diameter 14cm.use the value 3.14 for pie and do not round your answer be sure to include the correct unit in your answer  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784279 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The area of a circle is found by squaring the radius and multiplying by <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\">.  (<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\">, by the way, should be rendered in plain text as \"pi\" because \"pie\" is a pastry item with either a fruit or other sweet filling served as a dessert, or a savory filling served as either a main or side dish.)\r<BR>\n" );
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document.write( "You were given the diameter, 14 cm, so you need to first compute the radius which is precisely one-half of the diameter, namely 7 cm.\r<BR>\n" );
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document.write( "So, 7 cm squared is 49 multiplied by the required approximation for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\">, 3.14, results in 153.86 square centimeters.  And this is the answer required by the question.\r<BR>\n" );
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document.write( "However, for the question as stated, this answer is absolutely and demonstrably wrong.  Here is why:  ALL measurements are approximations.  You were given 14 cm as a measure of the diameter. But since you were given the approximate measurement to the nearest whole centimeter, you are only guaranteed that the true measurement is in the interval <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 13.5\ \leq\ D\ <\ 14.5\"> based on the rules for rounding. Therefore the true measure of the area, based on the given approximation of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \pi\"> is in the range\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 3.14\(\frac{13.5}{2}\)^2 \leq\ A\ <\ 3.14\(\frac{14.5}{2}\)^2\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 143.1\ \leq\ A\ <\ 165.0\ \ \"> square centimeters\r<BR>\n" );
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document.write( "Which renders the decimal fraction on the requested answer utterly meaningless.  If your instructor had wanted an answer correct to two decimal places s/he should have expressed the original diameter measurement as 14.00 centimeters.\r<BR>\n" );
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document.write( "Rule:  Never express the FINAL result of a calculation involving measurements to greater precision than the least precise given measurement.<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg\"><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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