document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160727>Question 1160727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that when adults with smartphones are randomly​ selected, 45​% use them in meetings or classes. If 5 adult smartphone users are randomly​ selected, find the probability that at least 3 of them use their smartphones in meetings or classes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784245 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is 3,4,5<BR>\n" );
document.write( "for 5 it is 0.45^5=0.0185<BR>\n" );
document.write( "for 4 it is 5(0.45)^4*0.55=0.1128; the 5 is the number of ways it can occur.<BR>\n" );
document.write( "for 3 it is 5C3*0.43^3*0.55^2=0.2757<BR>\n" );
document.write( "that sum is 0.4070\r<BR>\n" );
document.write( "\n" );
document.write( "Can do 1-binomcdf(5,.45,2 )on the calculator and that removes the 0,1,2 probability from the distribution.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );