document.write( "Question 1160843: Assume a normal distribution with known population variance. Calculate the lower
\n" ); document.write( "confidence limit (LCL) and upper confidence limit (UCL) for each of the following.
\n" ); document.write( "a. 𝑥̅ = 50; n = 64; 𝜎 = 40; α = 0.05
\n" ); document.write( "b. 𝑥̅ = 85; n = 225; 𝜎2 = 400; α = 0.01
\n" ); document.write( "c. 𝑥̅ = 510; n = 485; 𝜎 = 50; α = 0.10
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Algebra.Com's Answer #784244 by Boreal(15235)\"\" \"About 
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half-interval is z*sigma/sqrt(n), and this is added and subtracted to and from the mean to get the interval limits.\r
\n" ); document.write( "\n" ); document.write( "half-interval for a is z(0.975)*40/sqrt(64)=9.8
\n" ); document.write( "(40.2, 59.8)\r
\n" ); document.write( "\n" ); document.write( "half-interval for b is z(0.995)*20/sqrt (225). Variance is sigma^2 so have to take the square root of 400 for sigma.
\n" ); document.write( "=2.576*20/15=3.43
\n" ); document.write( "(81.57, 88.43)\r
\n" ); document.write( "\n" ); document.write( "half-interval for c is z(0.95)*50/sqrt(485)
\n" ); document.write( "=1.645*50/sqrt (485)=3.73
\n" ); document.write( "(506.27, 513.73)
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