document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160711>Question 1160711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7.	For a random variable that is normally distributed, with mean of 80 and standard deviation of 10, determine the probability that a simple random sample of 25 items will have a mean that is; A. greater than 78.  B. between 79 and 85.  C. less than 85.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #784234 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=784234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sigma/sqrt(n), and SE is 10/sqrt(25)=2<BR>\n" );
document.write( "so this becomes a normal diet with mean 80 and sd 2<BR>\n" );
document.write( "a. greater than 78 is a z>-1 or prob. 0.8413<BR>\n" );
document.write( "b. between 79 and 85 is z > -0.5 and +2.5 or probability 0.6853<BR>\n" );
document.write( "c. z less than 2.5 is probability 0.9938. </SPAN>\n" );
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