document.write( "Question 1160797: The cable of a suspension bridge hangs in the form of a parabola when the load is uniformly distributed horizontally. The distance
\n" ); document.write( "between the two towers is 1500 ft, the points of support of the cable on the towers are 220 ft above the roadway, and the lowest
\n" ); document.write( "point on the cable is 70 ft above the roadway. Find the vertical distance of the cable from a point in the roadway 150 ft from the
\n" ); document.write( "foot of a tower.
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Algebra.Com's Answer #784221 by Alan3354(69443)\"\" \"About 
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The cable of a suspension bridge hangs in the form of a parabola when the load is uniformly distributed horizontally. The distance between the two towers is 1500 ft, the points of support of the cable on the towers are 220 ft above the roadway, and the lowest point on the cable is 70 ft above the roadway. Find the vertical distance of the cable from a point in the roadway 150 ft from the
\n" ); document.write( "foot of a tower.
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\n" ); document.write( "Make the Origin the point midway between the towers and 70 feet above the roadway.
\n" ); document.write( "---> 3 points:
\n" ); document.write( "A(-750,220), B(0,0) and C(750,220)
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\n" ); document.write( "Find the equation of the parabola.
\n" ); document.write( "Then, find the y value at x = 600.
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\n" ); document.write( "email via the TY note for help or to check your work.
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\n" ); document.write( "PS A cable supporting its weight does form a parabola.
\n" ); document.write( "It's a catenary curve.\r
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