document.write( "Question 1160802: John is 3 times as old as Ken. Three years ago, he is four times as old as Joy. Find the sum of their ages. \n" ); document.write( "

Algebra.Com's Answer #784196 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
John 3k
\n" ); document.write( "Ken k
\n" ); document.write( "Joy j\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------
\n" ); document.write( "Three years ago, he is four times as old as Joy.
\n" ); document.write( "-----------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"He\" is \"John\".
\n" ); document.write( "Not \"is\", but \"WAS\".
\n" ); document.write( " $\"3k-3=4%28j-3%29\"$
\n" ); document.write( " $\"3k-3=4j-12\"$
\n" ); document.write( " $\"3k=4j-9\"$
\n" ); document.write( "not yet to answer the question.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I suspect either a mistake in the description, or some information was excluded. \n" ); document.write( "

\n" );