document.write( "Question 1160782: At an evening showing of the movie \"Divine Secrets of the Ya-Ya Sisterhood\", there were 42 more women than men in attendance. If there were 90 people in the theater, how many were women?
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Algebra.Com's Answer #784178 by saw(34) ![]() You can put this solution on YOUR website! Solution. \n" ); document.write( "Let x = men \n" ); document.write( "Let x+42 = women \n" ); document.write( "x+(x+42) = 90 \n" ); document.write( "Remove parentheses \n" ); document.write( "x+x+42 = 90 \n" ); document.write( "Collect the like terms \n" ); document.write( "2x+42 = 90 \n" ); document.write( "Move constant to the right side of the equation and change its sign \n" ); document.write( "2x = 90-42 \n" ); document.write( "Calculate the difference \n" ); document.write( "2x = 48 \n" ); document.write( "Divide both sides by 2 \n" ); document.write( "x = 24 \n" ); document.write( "x+42 \n" ); document.write( "Use substitution \n" ); document.write( "24+42 = 66 \n" ); document.write( "So the men were 24 and women were 66. \n" ); document.write( "Check----- \n" ); document.write( "x+(x+42) = 90\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |