document.write( "Question 1160782: At an evening showing of the movie \"Divine Secrets of the Ya-Ya Sisterhood\", there were 42 more women than men in attendance. If there were 90 people in the theater, how many were women?
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Algebra.Com's Answer #784178 by saw(34)\"\" \"About 
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Solution.
\n" ); document.write( "Let x = men
\n" ); document.write( "Let x+42 = women
\n" ); document.write( "x+(x+42) = 90
\n" ); document.write( "Remove parentheses
\n" ); document.write( "x+x+42 = 90
\n" ); document.write( "Collect the like terms
\n" ); document.write( "2x+42 = 90
\n" ); document.write( "Move constant to the right side of the equation and change its sign
\n" ); document.write( "2x = 90-42
\n" ); document.write( "Calculate the difference
\n" ); document.write( "2x = 48
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "x = 24
\n" ); document.write( "x+42
\n" ); document.write( "Use substitution
\n" ); document.write( "24+42 = 66
\n" ); document.write( "So the men were 24 and women were 66.
\n" ); document.write( "Check-----
\n" ); document.write( "x+(x+42) = 90\r
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