document.write( "Question 1160736: The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 1800 miles. What is the probability a certain tire of this brand will last between 56,220 miles and 56,760 miles?
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document.write( " 0.4920
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document.write( " 0.4649
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document.write( " 0.9813
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document.write( " 0.0180
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Algebra.Com's Answer #784158 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "this is between -3780/1800 or -2.1 \n" ); document.write( "and -3240/1800 or -1.8 \n" ); document.write( "That probability of z between those two values is 0.01807 \n" ); document.write( "last choice Is the best. \n" ); document.write( " |