document.write( "Question 1160733: Joe is x years old.
\n" ); document.write( "Sue is 3 years old younger than Joe.
\n" ); document.write( "Paul is twice old as joe.
\n" ); document.write( "The sum of their ages is 33.
\n" ); document.write( "How old is Joe? \n" ); document.write( "
Algebra.Com's Answer #784127 by saw(34)\"\" \"About 
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Solution.
\n" ); document.write( "Let Joe's age be x.
\n" ); document.write( "Sue's age be x-3.
\n" ); document.write( "Paul's age be 2x.
\n" ); document.write( "x+(x-3)+2x = 33
\n" ); document.write( "Remove parentheses
\n" ); document.write( "x+x-3+2x = 33
\n" ); document.write( "Collect the like terms
\n" ); document.write( "4x-3 = 33
\n" ); document.write( "Move constant to the right
\n" ); document.write( "4x = 33+3
\n" ); document.write( "Add the numbers
\n" ); document.write( "4x = 36
\n" ); document.write( "Divide both sides of the equation by 4
\n" ); document.write( "x = 9
\n" ); document.write( "Joe is 9 years old.
\n" ); document.write( "Sue is (9-3) = 6 years old.
\n" ); document.write( "Paul is 2x = 2*9 = 18 years old.
\n" ); document.write( "Check-----
\n" ); document.write( "x+(x-3)+2x = 33\r
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