document.write( "Question 1160720: Your sample consists of 72 subjects, with 53 successes. Calculate the test statistic, rounded to 2 decimal places. H0:p=0.69 H1<0.69 \n" ); document.write( "
Algebra.Com's Answer #784111 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "n = 72 is the sample size
\n" ); document.write( "x = 53 is the number of successes
\n" ); document.write( "phat = x/n = 53/72 = 0.736111 is the approximate sample proportion
\n" ); document.write( "p = 0.69 is the hypothesized population proportion\r
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\n" ); document.write( "\n" ); document.write( "Calculate the standard error (SE)
\n" ); document.write( "SE = sqrt(p*(1-p)/n)
\n" ); document.write( "SE = sqrt(0.69*(1-0.69)/72)
\n" ); document.write( "SE = 0.054505 which is approximate\r
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\n" ); document.write( "\n" ); document.write( "Use the values of phat,p and SE to find the z test statistic
\n" ); document.write( "z = (phat - p)/SE
\n" ); document.write( "z = (0.736111 - 0.69)/0.054505
\n" ); document.write( "z = 0.845996 also approximate
\n" ); document.write( "z = 0.85 rounding to two decimal places\r
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\n" ); document.write( "\n" ); document.write( "Answer: z = 0.85
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