document.write( "Question 1160648: Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 111. Two adults and three children must pay $ 79. Find the price of the adult's ticket and the price of a child's ticket. \n" ); document.write( "
Algebra.Com's Answer #784050 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Although not typical, here is an alternative solution method using elimination. \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "Subtract (2) from (1): \n" ); document.write( "(3) \n" ); document.write( "Now double (3) and subtract from (2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Plug c=15 into (3) to find a=17. \n" ); document.write( "ANSWER: adult ticket costs $17; child ticket costs $15. \n" ); document.write( "This method can be used -- either formally, as above, of informally, as below, because the difference between the two given cases is 1 adult and 1 child. \n" ); document.write( "This variation of a formal algebraic solution using elimination exactly follows an informal solution obtained by logical reasoning: \n" ); document.write( "3 adults and 4 children cost $111 \n" ); document.write( "2 adults and 3 children cost $79 \n" ); document.write( "Therefore, continuing the \"pattern\" of 1 less adult and 1 less children for $32 less... \n" ); document.write( "1 adult and 2 children cost $47 \n" ); document.write( "0 adult and 1 child cost $15 \n" ); document.write( "ANSWER: child $15; adult $32-$15 = $17 \n" ); document.write( " \n" ); document.write( " |