document.write( "Question 1160648: Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 111.  Two adults and three children must pay $ 79.  Find the price of the​ adult's ticket and the price of a​ child's ticket. \n" ); document.write( "
Algebra.Com's Answer #784050 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Although not typical, here is an alternative solution method using elimination.

\n" ); document.write( "(1) \"3a%2B4c+=+111\"
\n" ); document.write( "(2) \"2a%2B3c+=+79\"

\n" ); document.write( "Subtract (2) from (1):
\n" ); document.write( "(3) \"a%2Bc+=+32\"

\n" ); document.write( "Now double (3) and subtract from (2):
\n" ); document.write( "\"2a%2B3c+=+79\"
\n" ); document.write( "\"2a%2B2c+=+64\"
\n" ); document.write( "\"c+=+15\"

\n" ); document.write( "Plug c=15 into (3) to find a=17.

\n" ); document.write( "ANSWER: adult ticket costs $17; child ticket costs $15.

\n" ); document.write( "This method can be used -- either formally, as above, of informally, as below, because the difference between the two given cases is 1 adult and 1 child.

\n" ); document.write( "This variation of a formal algebraic solution using elimination exactly follows an informal solution obtained by logical reasoning:

\n" ); document.write( "3 adults and 4 children cost $111
\n" ); document.write( "2 adults and 3 children cost $79

\n" ); document.write( "Therefore, continuing the \"pattern\" of 1 less adult and 1 less children for $32 less...

\n" ); document.write( "1 adult and 2 children cost $47
\n" ); document.write( "0 adult and 1 child cost $15

\n" ); document.write( "ANSWER: child $15; adult $32-$15 = $17

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