document.write( "Question 1160679: Maria is now twice as old as Lenlen. Five years ago she was three times as old as Lenlen. Find their present ages. using polya method\r
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Algebra.Com's Answer #784049 by ikleyn(52800) $\"\"$ $\"About$

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document.write( "Let Lehlen  be x years old now;\r\n" );
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document.write( "then Maria is 2x years now.\r\n" );
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document.write( "Five years ago :  Maria was  2x-5 years old;\r\n" );
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document.write( "                  Lenlen was x-5 years old.\r\n" );
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document.write( "Equation :\r\n" );
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document.write( "    2x-5 = 3*(x-5)\r\n" );
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document.write( "Simplify and solve\r\n" );
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document.write( "    2x-5 = 3x - 15\r\n" );
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document.write( "    15-5 = 3x - 2x\r\n" );
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document.write( "    10   = x\r\n" );
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document.write( "ANSWER.  Lehlen is 10 years old now.  Maria is 20 years old now.\r\n" );
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document.write( "CHECK.  5 years ago  M was 15 years old;  L was 5 years old.   ! Correct !\r\n" );
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