document.write( "Question 1160656: a straight line with equation 2y = kx + h passes through the points (-3,6) and ( 1,11) find the value of k and of h\r
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Algebra.Com's Answer #784015 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"2y+=+kx+%2B+h\" passes through the points (\"-3\",\"6\") and ( \"1\",\"11\") \r
\n" ); document.write( "\n" ); document.write( "find the value of \"k\" and of\"+h\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y+=+kx+%2B+h\" use the point (\"-3\",\"6\")\r
\n" ); document.write( "\n" ); document.write( "\"2%2A6+=+k%28-3%29+%2B+h\"........solve for \"h\"\r
\n" ); document.write( "\n" ); document.write( "\"12+=+-3k+%2B+h\"\r
\n" ); document.write( "\n" ); document.write( "\"h=3k%2B12\"............eq.1\r
\n" ); document.write( "\n" ); document.write( "use the point ( \"1\",\"11\")\r
\n" ); document.write( "\n" ); document.write( "\"2%2A11+=+k%281%29+%2B+h\".....solve for \"h\"\r
\n" ); document.write( "\n" ); document.write( "\"22+=+k+%2B+h\"\r
\n" ); document.write( "\n" ); document.write( "\"h=22-k\"............eq.2\r
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\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have:\r
\n" ); document.write( "\n" ); document.write( "\"3k%2B12=22-k\"
\n" ); document.write( "\"3k%2Bk=22-12\"
\n" ); document.write( "\"4k=10\"
\n" ); document.write( "\"k=10%2F4\"
\n" ); document.write( "\"k=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "go to \"h=22-k\"............eq.2, plug in \"k\"\r
\n" ); document.write( "\n" ); document.write( "\"h=22-5%2F2\"
\n" ); document.write( "\"h=39%2F2\"\r
\n" ); document.write( "\n" ); document.write( "then your equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"2y+=+%285%2F2%29x+%2B+39%2F2\"\r
\n" ); document.write( "\n" ); document.write( "and in slope intercept form is:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%285%2F4%29x+%2B+39%2F4\"\r
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